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Home/ Questions/Q 6101371
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T13:29:33+00:00 2026-05-23T13:29:33+00:00

I am reading some code that looks like that: Class_Menu.php: <?php class Menu {

  • 0

I am reading some code that looks like that:

Class_Menu.php:

<?php
    class Menu {
        private $label;
        private $link;
        private $args;

        function __construct($label, $link, $args=array()) {
            $this->label=$label;
            $this->link=$link;
            $this->args=$args;
        }
...

Note how $args is defined as an array in the __construct. Why would one choose this approach rather than define $args in the var list:

<?php
    class Menu {
        private $label;
        private $link;
        private $args=array();

        function __construct($label, $link, $args) {
            $this->label=$label;
            $this->link=$link;
            $this->args=$args;
        }
...
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T13:29:34+00:00Added an answer on May 23, 2026 at 1:29 pm

    In the first example, $args is optional. The constructor can be called with only 2 arguments for $label and $link, and $args will be defined as an empty array.

    In the second example, the $args parameter is required.

    (opinion): I would have left $args = array() in the constructor AND when declaring the property so it’s easy to tell at a glance what type of var $args is.

    <?php
        class Menu {
            private $label;
            private $link;
            private $args = array();
    
            function __construct($label, $link, $args=array()) {
                $this->label=$label;
                $this->link=$link;
                $this->args=$args;
            }
    
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