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Home/ Questions/Q 361241
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T12:52:43+00:00 2026-05-12T12:52:43+00:00

I am reading the Algorithm Design Manual Second Edition and this is from an

  • 0

I am reading the Algorithm Design Manual Second Edition and this is from an exercise question. Quoting the question

A common problem for compilers and
text editors is determining whether
the parentheses in a string are
balanced and properly nested. For
example, the string ((())())()
contains properly nested pairs of
parentheses, which the strings )()(
and ()) do not. Give an algorithm that
returns true if a string contains
properly nested and balanced
parentheses, and false if otherwise.
For full credit, identify the position
of the first offending parenthesis if
the string is not properly nested and
balanced.

Question is under stacks,queues and lists category. Here is what I wrote in C#.

const char LeftParenthesis = '(';
const char RightParenthesis = ')';
bool AreParenthesesBalanced(string str, out int errorAt)
{
    var items = new Stack<int>(str.Length);
    errorAt = -1;
    for (int i = 0; i < str.Length; i++)
    {
        char c = str[i];
        if (c == LeftParenthesis)
            items.Push(i);
        else if (c == RightParenthesis)
        {
            if (items.Count == 0)
            {
                errorAt = i + 1;
                return false;
            }
            items.Pop();
        }
    }
    if (items.Count > 0)
    {
        errorAt = items.Peek() + 1;
        return false;
    }
    return true;
}

This works well. But I am not sure that this is the right method to approach this problem. Any better ideas are welcome.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T12:52:43+00:00Added an answer on May 12, 2026 at 12:52 pm

    I think this is the intention, but really you just need to decrement and increment a counter if you are only dealing with parenthesis. If you are dealing with the pairings of square brackets, angle brackets, curly braces or whatever character pairing you’d like to use, you’ll need a stack like you have done.

    You can also use a list, pulling the head element off and on, but really a stack is probably implemented as a list anyway –at least it is in ocaml.

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