Question

I am really confuse why in this small example i is still 0:

public static void main(String[] args) {
    int i = 0;
    inc(i);
    System.out.println(i);
}

private static void inc(int i) {
    i++;
}

probably very easy question but I dont see it

Answer 1

Java passes parameters by value.

So the i in the method inc is really just a copy of the “original” i in the main method. You increment that copy, but that has no influence on the original variable i outside.

See this question for a more detailed explanation.