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Home/ Questions/Q 198291
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T16:55:31+00:00 2026-05-11T16:55:31+00:00

I am really new to Haskell (Actually I saw Real World Haskell from O’Reilly

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I am really new to Haskell (Actually I saw “Real World Haskell” from O’Reilly and thought “hmm, I think I’ll learn functional programming” yesterday) and I am wondering: I can use the construct operator to add an item to the beginning of a list:

1 : [2,3]
[1,2,3]

I tried making an example data type I found in the book and then playing with it:

--in a file
data BillingInfo = CreditCard Int String String
| CashOnDelivery
| Invoice Int
deriving (Show)

--in ghci
 $ let order_list = [Invoice 2345]
 $ order_list
[Invoice 2345]
 $ let order_list = CashOnDelivery : order_list
 $ order_list
[CashOnDelivery, CashOnDelivery, CashOnDelivery, CashOnDelivery, CashOnDelivery, CashOnDelivery, CashOnDelivery, CashOnDelivery, CashOnDelivery, CashOnDelivery, CashOnDelivery, CashOnDelivery, CashOnDelivery, CashOnDelivery, ...-

etc… it just repeats forever, is this because it uses lazy evaluation?

— EDIT —

okay, so it is being pounded into my head that let order_list = CashOnDelivery:order_list doesn’t add CashOnDelivery to the original order_list and then set the result to order_list, but instead is recursive and creates an infinite list, forever adding CashOnDelivery to the beginning of itself. Of course now I remember that Haskell is a functional language and I can’t change the value of the original order_list, so what should I do for a simple “tack this on to the end (or beginning, whatever) of this list?”
Make a function which takes a list and BillingInfo as arguments, and then return a list?

— EDIT 2 —

well, based on all the answers I’m getting and the lack of being able to pass an object by reference and mutate variables (such as I’m used to)… I think that I have just asked this question prematurely and that I really need to delve further into the functional paradigm before I can expect to really understand the answers to my questions… I guess what i was looking for was how to write a function or something, taking a list and an item, and returning a list under the same name so the function could be called more than once, without changing the name every time (as if it was actually a program which would add actual orders to an order list, and the user wouldn’t have to think of a new name for the list each time, but rather append an item to the same list).

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  1. Editorial Team
    Editorial Team
    2026-05-11T16:55:31+00:00Added an answer on May 11, 2026 at 4:55 pm

    You do this:

    $ let order_list = [Invoice 2345]
    $ let order_list = CashOnDelivery : order_list
    

    The important thing to note here is that you are not just adding a CashOnDelivery item to your first order_list. You are defining a new variable order_list that has nothing to do with the first one. This is a recursive definition, the order_list on the right side refers to the order_list you are defining on the left, not the one defined in the previous line. Because of this recursion you get an infinite list.

    I suspect you really wanted to do something like this:

    $ let order_list = [Invoice 2345]
    $ order_list
    [Invoice 2345]
    $ let order_list2 = CashOnDelivery : order_list
    $ order_list2
    [CashOnDelivery, Invoice 2345]
    
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