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Home/ Questions/Q 872693
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T10:49:21+00:00 2026-05-15T10:49:21+00:00

I am received the following error while trying to implement a C# extension function

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I am received the following error while trying to implement a C# extension function in XSLT.

Extension function parameters or return values which have CLR type ‘Char[]’ are not supported.**

code:

<xsl:variable name="stringList">
  <xsl:value-of select="extension:GetList('AAA BBB CCC', ' ')"/>
</xsl:variable> 

<msxsl:script language="C#" implements-prefix="extension">
<![CDATA[

public string[] GetList(string str, char[] delimiter)
{
   ...
   ...
   return str.Split(delimiter, StringSplitOptions.None);
}

]]>
</msxsl:script>

Can someone explain this error message and how to get past it?

EDIT: I need a solution that still lets me implement the split function and make use of the array returned.

Thanks!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T10:49:21+00:00Added an answer on May 15, 2026 at 10:49 am

    XSLT extension methods must return a type that is supported within XSL transformations. The following table shows the W3C XPath types and their corresponging .NET type:

    W3C XPath Type        | Equivalent .NET Class (Type)
    ------------------------------------------------------
    String                | System.String
    Boolean               | System.Boolean
    Number                | System.Double
    Result Tree Fragment  | System.Xml.XPath.XPathNavigator
    Node Set              | System.Xml.XPath.XPathNodeIterator
    

    The table is taken from the section Mapping Types between XSLT and .NET in this MSDN Magazine article.

    Instead of returning a string[] array you would have to return an XPathNodeIterator like it is done in the following example:

    <msxsl:script implements-prefix="extension" language="C#">
    <![CDATA[
    
    public XPathNodeIterator GetList(string str, string delimiter)
    {
        string[] items = str.Split(delimiter.ToCharArray(), StringSplitOptions.None);
        XmlDocument doc = new XmlDocument();
        doc.AppendChild(doc.CreateElement("root"));
        using (XmlWriter writer = doc.DocumentElement.CreateNavigator().AppendChild())
        {
            foreach (string item in items)
            {
                writer.WriteElementString("item", item);
            }
        }
        return doc.DocumentElement.CreateNavigator().Select("item");
    }
    ]]>
    </msxsl:script>
    

    In your XSL transform you can then iterate over the elements in the returned node set using xsl:for-each:

    <xsl:template match="/">
        <root>
            <xsl:for-each select="extension:GetList('one,two,three', ',')">
                <value>
                    <xsl:value-of select="."/>
                </value>
            </xsl:for-each>
        </root>
    </xsl:template>
    
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