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Home/ Questions/Q 7856031
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T20:34:00+00:00 2026-06-02T20:34:00+00:00

I am receiving a html form. This works fine when 2 or more elements

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I am receiving a html form. This works fine when 2 or more elements in array, but when only one element is received I get error users[t] is null in fireBug?

var users = form.elements["uname[]"];

for(t in users) {
  dataString += "User: "+users[t].value+"\n"
}

this solved it:

if( typeof users.value === 'string' ) {
   users = [ users ];
}
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  1. Editorial Team
    Editorial Team
    2026-06-02T20:34:02+00:00Added an answer on June 2, 2026 at 8:34 pm

    You could check if the variable is a string and convert it to an array:

    if( typeof users === 'string' ) {
        users = [ users ];
    }
    

    For iterating arrays for-in should be avoided, that statement is meant to enumerate object properties. You could try using a better loop, something like:

    var userCount = users.length;
    for (var i = 0; i < userCount; i++) {
          dataString += "User: "+users[i].value+"\n"
    }
    

    You could also base a test on the length. If the object is single it will return undefined for length.

    var userCount = users.length; //Get user count
    if ( userCount == undefined ) { //Returned undefined if not an array.
        users = [ users ]; //Convert to array
    }
    
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