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Home/ Questions/Q 8544309
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T12:31:33+00:00 2026-06-11T12:31:33+00:00

I am recursively generating few objects, which need a contiguous, unique id. How can

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I am recursively generating few objects, which need a contiguous, unique id. How can I guarantee (easiest) the synchronization in python 2.7.

iid = 1

def next_id():
    iid += 1
    return iid

def process():
    # .. do something
    id = next_id()
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  1. Editorial Team
    Editorial Team
    2026-06-11T12:31:34+00:00Added an answer on June 11, 2026 at 12:31 pm

    Use a mutex:

    import threading
    iid = 1
    iid_lock = threading.Lock()
    
    def next_id():
        global iid
        with iid_lock:
            result = iid
            iid += 1
        return result
    

    You might like to hide the internals in a class:

    class IdGenerator(object):
        def __init__(self):
            self.cur_id = 1
            self.lock = threading.Lock()
        def next_id(self):
            with self.lock:
                result = self.cur_id
                self.cur_id += 1
            return result
    

    EDIT: Based on the comments, it seems like you’re not using threads. This means you don’t need the locking mechanism at all. What you initially wrote would be sufficient, though you need the global keyword to make the global variable mutable:

    iid = 1
    def next_id():
        global iid
        res = iid
        iid += 1
        return res
    
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