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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T02:44:02+00:00 2026-05-19T02:44:02+00:00

I am requesting youtube search terms for use with jquery autocomplete, but am having

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I am requesting youtube search terms for use with jquery autocomplete, but am having a hard time converting the URL response into a proper format.

In my (Django/Python) view I do:

data2 = urllib2.urlopen('http://suggestqueries.google.com/complete/search?hl=en&ds=yt&client=youtube&hjson=t&jsonp=window.yt.www.suggest.handleResponse&q=jum&cp=3')

(I hardcoded the search term = ‘jump’ for simplicity)

If I do data2.read() I get what I believe is JSON (copy-pasting the url into a browser also returns this.)

window.yt.www.suggest.handleResponse(["jum",[["jumpstyle","","0"],["jump","","1"],["jump around","","2"],["jump on it","","3"],["jumper","","4"],["jump around house of pain","","5"],["jumper third eye blind","","6"],["jumbafund","","7"],["jump then fall taylor swift","","8"],["jumpstyle music","","9"]],"","","","","",{}])

I need to return this in a format that jquery autocomplete can read. I know it will work if I can get it into a list, for example, mylist = ['jumpstyle', 'jump', 'jump around', ...]

and then convert it back into json before returning it:

json.dumps(mylist)

(This works if I directly define mylist directly as written above.)

But I cannot get from the data that is returned by the URL to either a simple list (which I then convert back into JSON) or to some form of JSON that I can return directly to be used by auto complete.

I’ve tried, among other things,

j2 = json.loads(data2)

and

j2 = json.loads(data2.read())

Hope someone can help!

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  1. Editorial Team
    Editorial Team
    2026-05-19T02:44:03+00:00Added an answer on May 19, 2026 at 2:44 am

    remove the &jsonp=window.yt.www.suggest.handleResponse part

    import json
    import urllib2
    
    data = urllib2.urlopen('http://suggestqueries.google.com/complete/search?hl=en&ds=yt&client=youtube&hjson=t&q=jum&cp=3')
    
    j = json.load(data)
    k = [i for i, j, k in j[1]]
    l = json.dumps(k)
    
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