Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 812803
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 15, 20262026-05-15T01:15:36+00:00 2026-05-15T01:15:36+00:00

I am returning some data (example below) and saving it to a jQuery object

  • 0

I am returning some data (example below) and saving it to a jQuery object (or is this an array and I am confusing the two?) when I log the variable that is the object it has the values I am looking for but how do I access the data inside this object?

code

$itemPosition = {
    'top': $item.offset().top,
    'left':$item.offset().left
},

console.log($itemPosition);

This would log out (the in this case expected) top: 0 & left: 490.

But how can I know work with those values?

Also, while this it is probably obvious I am still in the early stages of learning jQuery/Javascript rest assured that reference books are on their way, but so far the SO community has been invaluable to my learning, so thanks for reading!

J.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-15T01:15:36+00:00Added an answer on May 15, 2026 at 1:15 am

    This is a plain javascript object. Not a jQuery object and not an array.

    Accessing properties of an object would work like so:

     $itemPosition.top;
     $itemPosition.left;
    

    Placing a $ as the first character of the name is valid, but may lead to confusion as it is a convention used when storing a jQuery object.

    Another valid way to access the properties of your object is to use square brackets, as in:

     $itemPosition['top'];
     $itemPosition['left'];
    

    Using the square bracket method, you can also pass in variables, like so:

    var myTopString = 'top';
    
    $itemPosition[myTopString];
    

    If you want to iterate over all the values in your object, you can do the following:

    for(var n in $itemPosition) {
        alert( n + ': ' + $itemPosition[n] );
    }
    

    This will alert() the key and value of each object property. As you can see, it uses the square bracket method, passing in the key for each property stored in the variable n.

    That’s all I have to say about that. -F. Gump

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 408k
  • Answers 408k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer I think I understand your problem. You are saying that… May 15, 2026 at 6:57 am
  • Editorial Team
    Editorial Team added an answer You want double *la[3];. As you have it, la isn't… May 15, 2026 at 6:57 am
  • Editorial Team
    Editorial Team added an answer You can use the AssetManager and ZipInputStream http://developer.android.com/reference/android/content/res/AssetManager.html ZipInputStream in… May 15, 2026 at 6:57 am

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.