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Home/ Questions/Q 630909
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T19:54:25+00:00 2026-05-13T19:54:25+00:00

I am running in to OpenURI::HTTPError: 403 Forbidden error when I try to open

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I am running in to OpenURI::HTTPError: 403 Forbidden error
when I try to open a URL with a comma (OR other special characters like .).
I am able to open the same url in a browser.

require 'open-uri'
url = "http://en.wikipedia.org/wiki/Thor_Industries,_Inc."
f = open(url)
# throws OpenURI::HTTPError: 403 Forbidden error

How do I escape such URL?

I have tried to escape the url with CGI::escape and I get the same error.

f = open(CGI::escape(url))
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  1. Editorial Team
    Editorial Team
    2026-05-13T19:54:26+00:00Added an answer on May 13, 2026 at 7:54 pm

    Typically, one would simply require the module cgi, then use CGI::escape(str).

    require 'cgi'
    require 'open-uri'
    escaped_page = CGI::escape("Thor_Industries,_Inc.")
    url = "http://en.wikipedia.org/wiki/#{escaped_page}"
    f = open(url)
    

    However, this doesn’t seem to work for your particular instance, and still returns a 403. I’ll leave this here for reference, regardless.


    Edit: Wikipedia is refusing your requests because it suspects that you are a bot. It would seem that certain pages that are clearly content are granted to you, but those that don’t match its “safe” pattern (e.g. those that contain dots or commas) are subject to its screening. If you actually output the content (I did this with Net::HTTP), you get the following:

    Scripts should use an informative User-Agent string with contact information, or they may be IP-blocked without notice.

    Providing a user-agent string, however, solves the issue:

    open("http://en.wikipedia.org/wiki/Thor_Industries,_Inc.",
      "User-Agent" => "Ruby/#{RUBY_VERSION}")
    
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