I am running into a frustrating problem with a PHP script that’s supposed to allow me to edit individual rows within my MySQL database.
This is the file where all of the rows from the database are displayed; it works just like it’s supposed to.
<table cellpadding="10">
<tr>
<td>ID</td>
<td>First Name</td>
<td>Last Name</td>
<td>E-mail</td>
<td>Phone</td>
</tr>
<?php
$username="username here";
$password="password here";
$database="database name here";
mysql_connect(localhost,$username,$password);
@mysql_select_db($database) or die( "Unable to select database");
$query="SELECT * FROM students";
$result=mysql_query($query);
mysql_close();
while ($row=mysql_fetch_array($result)){
echo ("<tr><td>$row[id]</td>");
echo ("<td>$row[first]</td>");
echo ("<td>$row[last]</td>");
echo ("<td>$row[email]</td>");
echo ("<td>$row[phone]</td>");
echo ("<td><a href=\"StudentEdit.php?id=$row[id]\">Edit</a></td></tr>");
}
echo "</table>";
?>
As you can see, each row has an “Edit” link that is supposed to allow the user to edit that individual student’s data. Here, then, is StudentEdit.php:
<?php
$username="username";
$password="password";
$database="database";
mysql_connect(localhost,$username,$password);
$student_id = $_GET[id];
$query = "SELECT * FROM students WHERE id = '$student_id'";
$result = mysql_query($query);
$row = mysql_fetch_array($result);
mysql_close();
?>
<form method="post" action="EditStudentData.php" />
<table>
<tr>
<td><input type="hidden" name="id" value="<? echo "$row[id]" ?>"></td>
</tr>
<tr>
<td>First Name:</td>
<td><input type="text" name="first" value="<? echo "$row[first]" ?>"></td>
</tr>
<tr>
<td>Last Name:</td>
<td><input type="text" name="last" value="<? echo "$row[last]" ?>"></td>
</tr>
<tr>
<td>Phone Number:</td>
<td><input type="text" name="phone" value="<? echo "$row[phone]" ?>"></td>
</tr>
<tr>
<td>E-mail:</td>
<td><input type="text" name="email" value="<?echo "$row[email]" ?>"></td>
</tr>
</table>
</form>
When I execute this, however, I get the following error message:
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home4/lukaspl1/public_html/StudentEdit.php on line 12
Any ideas what’s wrong, and how to fix it?
Thank you in advance!
StudentEdit.php: you forgot to call
@mysql_select_db($database) or die( "Unable to select database");before you executed the query