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Home/ Questions/Q 7529203
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T04:35:47+00:00 2026-05-30T04:35:47+00:00

I am running into the org.hibernate.LazyInitializationException error when I try to access a lazy

  • 0

I am running into the org.hibernate.LazyInitializationException error when I try to access a lazy loaded exception when excecuting the following:

@Transactional
public void displayAddresses()
{
     Person person = getPersonByID(1234);
     List<Address> addresses = person.getAddresses(); // Exception Thrown Here

     for(Address address : addresses)
          System.out.println(address.getFullAddress());
}

My entities look like this:

@Entity
@Table("PERSON_TBL")
public class Person
{
     ...

     @OneToMany(cascade=CascadeType.ALL, targetEntity=Address.class, mappedBy="person")
     private List<Address> addresses;

     ...
}

@Entity
@Table("ADDRESS_TBL")
public class Address
{
     ...

     @ManyToOne(targetEntity=Person.class)
     @JoinColumn(name="PERSON_ID", referencedColumnName="PERSON_ID")
     Person person;

     ...
}

I was under the impression that by using the @Transactional annotation in my displayAddresses() method, it would keep the session alive until the method was completed, allowing me to access the lazy-loaded Address collection.

Am I missing something?

EDIT

In accordance with Tomasz’s advice: Within my displayAddresses() method, the status of TransactionSynchronizationManager.isActualTransactionActive(), turned out to be false.

That does narrow down the problem, but why would my Transaction not be active at this point?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T04:35:49+00:00Added an answer on May 30, 2026 at 4:35 am

    Having <tx:annotation-driven /> in my configuration file and using a Spring-managed version of my service class (to call the displayAddresses() method) did the trick.

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