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Home/ Questions/Q 7489451
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T15:14:58+00:00 2026-05-29T15:14:58+00:00

I am running my Application from a network-share. For example: \server\startProgramm.bat The Code in

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I am running my Application from a network-share. For example: “\server\startProgramm.bat”
The Code in my startProgramm.bat:

java -jar %~dp0\app.jar

I need to open some config files. It is working local if i try to open them with:

new File("").getAbsolutePath() + "\\" + filename

but not on my Network share.

The config-files are in a subdir of the dir where my jar and bat files are.

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  1. Editorial Team
    Editorial Team
    2026-05-29T15:14:59+00:00Added an answer on May 29, 2026 at 3:14 pm
    new File("\\\\servername\\sharedDirectoryOnServer\\fileOnServer");
    

    “Ok, this worked, but is there something like CurrentWorkDir?”

    The current working directory is (by default) the one your program runs in. You can not change it within java (see here:
    Changing the current working directory in Java?
    ),
    the best practice is to just concatenate the server-path and file-name; but i think (not sure) it is also possible to start your program from the server (java \\server\\path\\myprog where there’s a myprog.class in that directory) and make the working directory default to that path.

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