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Home/ Questions/Q 6755011
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T13:20:58+00:00 2026-05-26T13:20:58+00:00

I am running the following code. What it does is take a text file,

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I am running the following code. What it does is take a text file, splits it into parts that end with ‘_part’ ending and than calls the same script with a flag to process the files – uploading the content to a Drupal system.

What happens is that the script runs and finishes the work, all invoked scripts finish too and I can see the results. but each time after I run it the web server stops responding. Is there anything basic that I am missing or doing wrong?

  if(isset($argv[3])){
    $isSplit = $argv[3] == 'true' ? true : false;
  }      
  if($isSplit){                  
    $fileSplitter = new CSVFileParts($fileName);
    $parts = $fileSplitter->split_file();
    echo 'Splited file to '.$parts.' parts'.PHP_EOL;
    for($part =0; $part < $parts; $part++){            
      echo shell_exec('php Service.php u ./partial_files/'.basename($fileName).'.part_'.$part.' false > /dev/null 2>/dev/null &');
    }        
  }else{                            
    $log->lwrite('uploading '.$argv[2]); 
    $drupalUploader = new DrupalUploader($fileName, $log);
    $drupalUploader->upload();        
  }
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T13:20:59+00:00Added an answer on May 26, 2026 at 1:20 pm

    shell_exec — Execute command via shell and return the complete output as a string

    shell_exec expects the file handle to be open, but you redirect everything to /dev/null and detach it.

    As you plan to detach the process and remove all the output, you should use exec() and escapeshellcmd()

    see: http://www.php.net/manual/en/function.exec.php

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