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Home/ Questions/Q 8245315
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T22:08:17+00:00 2026-06-07T22:08:17+00:00

I am running this below code but it returns an error as: undefined index:

  • 0

I am running this below code but it returns an error as: "undefined index: value"

$two_tier= mysql_query("
    SELECT Count(1)
    FROM(
        SELECT `login_id`
        FROM `data`
        WHERE Year(`start_at`) = Year(Date_sub(Now(), INTERVAL 1 month))
        AND Month(`start_at`) = Month(Date_sub(Now(), INTERVAL 1 month)) 
        AND end_at > Date_add(start_at, INTERVAL 5 minute) 
        GROUP  BY `login_id`
        HAVING Count(`login_id`) > 1
    ) AS Value
");

$two_cnt = mysql_fetch_assoc($two_tier);
echo $two_cnt['value'];

I am trying to get the “value”. Little help, please.

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  1. Editorial Team
    Editorial Team
    2026-06-07T22:08:18+00:00Added an answer on June 7, 2026 at 10:08 pm
    SELECT Count(1) as my_value
    FROM   (SELECT `login_id` 
            FROM   `data` 
            WHERE  ( Year(`start_at`) = Year(Date_sub(Now(), INTERVAL 1 month)) 
                     AND Month(`start_at`) = Month(Date_sub(Now(), INTERVAL 1 month) 
                                             ) ) 
                   AND ( end_at > Date_add(start_at, INTERVAL 5 minute) ) 
            GROUP  BY `login_id` 
            HAVING Count(`login_id`) > 1) AS Value
    
    
    $two_cnt = mysql_fetch_assoc($two_tier);
    echo $two_cnt['my_value'];
    

    you select your FROM as Value, but result of first select isn’t in that Value, you need one more AS

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