Question

I am scrapping a site using scrapy framework and having trouble clicking on a javascript link for opening another page.

I can identify the code on the page as:

<a class="Page" alt="Click to view job description" title="Click to view job description" href="javascript:sysSubmitForm('frmSR1');">Accountant&nbsp;</a>

can any one suggest me how to execute that javascript in scaroy and get another page through i can fetch data from that page.

Thanks in advance

Answer 1

Checkout the below snipped on how to use scrapy with selenium. Crawling will be slower as you aren’t just downloading the html but you will get full access to the DOM.

Note: I have copy-pasted this snippet as the links previously provided no longer work.

# Snippet imported from snippets.scrapy.org (which no longer works)

from scrapy.contrib.spiders import CrawlSpider, Rule
from scrapy.contrib.linkextractors.sgml import SgmlLinkExtractor
from scrapy.selector import HtmlXPathSelector
from scrapy.http import Request

from selenium import selenium

class SeleniumSpider(CrawlSpider):
    name = "SeleniumSpider"
    start_urls = ["http://www.domain.com"]

    rules = (
        Rule(SgmlLinkExtractor(allow=('\.html', )),
        callback='parse_page',follow=True),
    )

    def __init__(self):
        CrawlSpider.__init__(self)
        self.verificationErrors = []
        self.selenium = selenium("localhost", 4444, "*chrome", "http://www.domain.com")
        self.selenium.start()

    def __del__(self):
        self.selenium.stop()
        print self.verificationErrors
        CrawlSpider.__del__(self)

    def parse_page(self, response):
        item = Item()

        hxs = HtmlXPathSelector(response)
        #Do some XPath selection with Scrapy
        hxs.select('//div').extract()

        sel = self.selenium
        sel.open(response.url)

        #Wait for javscript to load in Selenium
        time.sleep(2.5)

        #Do some crawling of javascript created content with Selenium
        sel.get_text("//div")
        yield item