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Home/ Questions/Q 7508839
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T22:45:06+00:00 2026-05-29T22:45:06+00:00

I am sending an ajax request to a php file as shown here: function

  • 0

I am sending an ajax request to a php file as shown here:

function checkDB(code, userid)
{

  $.ajax({
  type: "POST",
  url: "<?php bloginfo('template_url'); ?>/profile/check_code.php",
  data: 'code='+code+'userid='+userid,
  datatype: "html",
  success: function(result){

       if(result == 0)
        {
            $('#success').html( code + ' has been redeemed!');
            // alert('success');//testing purposes
        }
        else if(result == 2)
        {
            $('#err').html(  code + ' already exists and has already been redeemed....');
            //alert('fail');//testing purposes
        }else if(result == 1){
            $('#err').html(  code + ' redeem code doesnt exist');      
        }

        alert(result);      
      }
  })

}

This is sent calling the function on submit, like so:

<form method="post" class="sc_ajaxxx" id="sc_add_voucherx" name="sc_ajax"  
     onsubmit="checkDB(document.sc_ajax.sc_voucher_code.value, <?php echo $user_id ?>); return false;">
</form>

The problem is that the user id php variable is not getting sent to the check_code.php page by ajax. or at least I cant seem to echo the id back to the page.

Is this the correct way of passing multiple values to a server-side page? Without the userid passing over, it works fine just passing over the code.

Thanks guys 🙂

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T22:45:08+00:00Added an answer on May 29, 2026 at 10:45 pm

    Here is how POST data should be formatted:

    key1=value1&key2=value2&key3=value3
    

    In your case (note the & as a separator):

    'code=' + code + '&userid=' + userid
    

    But jQuery does that for you if you specify your data as an object:

    data: { code: code, userid: userid }
    
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