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Home/ Questions/Q 6382361
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T02:30:45+00:00 2026-05-25T02:30:45+00:00

I am (still) dealing with a tree structure in a Python program. Each node

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I am (still) dealing with a tree structure in a Python program.
Each node in a tree has a dictionary “children”, whose keys hold arc information, and values
are the child nodes. (And each node has a (parent, parent_arc) pair, where parent is its parent node and parent_arc is the arc by which the parent node link this node.)

Now I want to prune a subtree, whose root is a child of a node N. Say the child is N.children[a].

del N.children[a] simply won’t release the memory occupied by the subtree. Do I have to implement a method to delete every node in the subtree? How can I do this ? Do I need to re-define the node class for efficient subtree pruning?

Thank you!

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  1. Editorial Team
    Editorial Team
    2026-05-25T02:30:46+00:00Added an answer on May 25, 2026 at 2:30 am

    When A -> B and B -> A you have reference cycles. A good way to get around that is to have the children use weak references to point back to the parent. Something like this:

    import weakref
    class Node():
        parent = None
        child = None
        @property
        def parent(self):
            parent = self._parent()
            if parent is not None:
                return parent
            raise ValueError("parent has been deleted")
        @parent.setter     # python 2.6+
        def parent(self, parent):
            self._parent = weakref.ref(parent)
    

    Now, the node does not have a direct link to its parent, and when you delete the child it really will go away*. (You may need to use the same method for the parent_arc.)

    *Note that even though Python will release the objects more quickly if no reference cycles exist, it may not give that memory back to the OS.

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