Question

I am still trying to figure out how to use json.. can someone please help me understand how to deal with this response. My query is :

$.ajax({
url: s7query,
dataType: 'jsonp',
success: function(){
// how do I deal with the response?
} 
});

The json I am querying returns (with either a 1 or 0):

s7jsonResponse(
{"catalogRecord.exists":"1"},"");

All I need from this is the number and put that into a variable so I can then run conditional logic against that result. Thanks for any help understanding this…

If I try and handle the success with any function firebug just returns that s7jsonResponse is not defined. I tried to define it as a variable outside of the request. Now I see in firebug it is returning the json from all the requests, however it is returning them as errors and now says s7jsonResponse is not a function. I think I am close.. please help!

Answer 1

Ok, I missed the jsonp part! All you need is to define a method for s7jsonResponse.

function s7jsonResponse (jsonData, someString) {
    alert(jsonData["catalogRecord.exists"]);
    // deal with the response here
}

See this for details on JSONP

initial response

I noticed that catalogRecord.exists, this has a . in it and it won’t extract. If you don’t have a strong reason to do so, you could change it to catalogRecordExists and use below solution.

$.ajax({ 
url: s7query, 
dataType: 'json', //removed jsonp in the last edit
success: function(data){ // this is the method that executes on success
            // parseJSON is not required as you already put it in dataType
            // alert(($.parseJSON(data))["catalogRecord.exists"]); 
            alert(data["catalogRecord.exists"]);
         }
});

Note:
The data that you send back should = {"catalogRecord.exists":"1"}

You can use $.getJSON to do the same(it internally calls $.ajax)