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Home/ Questions/Q 7628387
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T05:35:16+00:00 2026-05-31T05:35:16+00:00

I am storing multiple objects into a config array. for example like this class

  • 0

I am storing multiple objects into a config array.

for example like this

class Test
{
    private $config = array();

    public function __construct()
    {
        $this->abc();
        $this->def();
    }

    public function abc()
    {
        $this->config['abc'] = new someClass('abc');
    }

    public function def()
    {
        $this->config['def'] = new someClass('def');
    }

    public function printTest()
    {
        return $this->config;
    }
}

class someClass
{
    public function __construct($value)
    {
        echo $value;
    }
}

my problem that i do see the object data when I print_r the config variable. What I cannot understand is why I cannot echo out the value of the first object abc after i try storing the second object def into the config array.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T05:35:17+00:00Added an answer on May 31, 2026 at 5:35 am

    When you want to print config[‘def’] you need to express that that is the data you want. Now that

    $this->config 
    

    is

    array('abc'=>'abc', 'def'=>'def')
    

    you just say

    return $this->config['def'];  
    

    Personally, I feel like a function named printSomething() should print the data to the screen (or atleast return a string, so I’d say

    function printConfig()
    {
        $tmp = "";
        foreach($this->config as $key=>$value)
        {
            $tmp .= "Config option:{$key} value is {$value}<br>";
        }
        return $tmp;
    }
    
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