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Home/ Questions/Q 6966701
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T16:13:32+00:00 2026-05-27T16:13:32+00:00

I am struggling with a problem, which I can’t understand why it doesn’t work.

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I am struggling with a problem, which I can’t understand why it doesn’t work. How do I pass a variable through the double obj and convert to int?
Why does it not work in the top code snippet, but it works in the bottom code snippet below the line?

The only difference seems to be adding an extra variable, which is also typed as a double?

//Converting double to int using helper

//This doesn't work- gets error message
//Cannot invoke intValue() on the primitive type double

double doublehelpermethod = 123.65;
double doubleObj = new Double( doublehelpermethod);
System.out.println("The double value is: "+ doublehelpermethod.intValue());
//--------------------------------------------------------------------------
//but this works! Why?

Double d = new Double(123.65);
System.out.println("The double object is: "+ doubleObj);
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T16:13:33+00:00Added an answer on May 27, 2026 at 4:13 pm

    The double is a primitive type, while the Double is a regular Java class. You cannot call a method on a primitive type. The intValue() method is however available on the Double, as shown in the javadoc

    Some more reading on those primitive types can be found here

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