Question

I am struggling with an idea I want put into a python script. I’m not even sure how to ask the most appropriate question as I’ve been surfing through the net trying to find what I want with no luck.

Basically, I have a script that does a simple calculation:

divider = int(math.ceil(df.scale / 3000))

This is because I want ‘ divider’ to return the value divided by 3000 and always rounded up. I want to use that value to help me return letters.

So, it goes like this:

if 1 returns then I want a to return ‘A’
if 2 returns, then I want to create ‘A’, ‘B’
if 3 returns, then I want to create ‘A’, ‘B’, ‘C’
and so on….

My end result is, that I want to save some files. ‘divider’ will determine how many files I want to save and then each file will recursively be named with the letter in it (i.e. FileA, FileB, FileC…)

Ok, I know my question isn’t exactly well put together, but I’m struggling with the logic, so if you need some clarity, please let me know.

Answer 1

Do you mean something like:

for i in range(int(math.ceil(df.scale / 3000))):
  # i will contain 0, 1, 2, ...
  # letter will contain 'A', 'B', 'C', ...
  letter = chr(ord('A') + i)

Or if you need the actual list:

[chr(ord('A') + i) for i in range(int(math.ceil(df.scale / 3000)))]

You can also use string.ascii_uppercase for a list of uppercase letters and slice it as you need:

from string import ascii_uppercase

print list(ascii_uppercase)[:int(math.ceil(df.scale / 3000))]