Question

I am stuck again trying to get my data in a format that I need it in. I have a text field that looks like this.

"deangelo 001 deangelo

local origin of name: italain

from the american name deangelo

meaning: of the angels

emotional spectrum • he is a fountain of joy for all.

personal integrity • his good name is his most precious asset.
personality • it’s hard to soar with eagles when you’re surrounded by
turkeys! relationships • starts slowly, but a relationship with
deangelo builds over time. travel & leisure • a trip of a lifetime
is in his future.

career & money • a gifted child, deangelo will need to be
challenged constantly.

life’s opportunities • joy and happiness await this blessed person.

deangelo’s lucky numbers: 12 • 38 • 18 • 34 • 29 • 16

"

What would the best way be in Postgresql to remove the carriage returns and new lines? I’ve tried several things and none of them want to behave.

select regexp_replace(field, E'\r\c', '  ', 'g') from mytable
    WHERE id = 5520805582

SELECT regexp_replace(field, E'[^\(\)\&\/,;\*\:.\>\<[:space:]a-zA-Z0-9-]', ' ')
    FROM mytable
    WHERE field~ E'[^\(\)\&\/,;\*\:.\<\>[:space:]a-zA-Z0-9-]'
    AND id = 5520805582;

Answer 1

select regexp_replace(field, E'[\\n\\r]+', ' ', 'g' )

read the manual http://www.postgresql.org/docs/current/static/functions-matching.html