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Asked: 2026-05-21T19:51:27+00:00

I am stuck trying to combine a like with a left join in Sybase.

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I am stuck trying to combine a like with a left join in Sybase.

For example (although in my case it’s a bit more complicated), I am looking for text that neither contains an o nor an i.

I am able to do the opposite, that is, text containing either of these letters:

select numbers.name from 
(
      select 'one'   name union all
      select 'two'   name union all
      select 'three' name union all -- neither %o% nor %i%
      select 'four'  name union all
      select 'five'  name union all
      select 'six'   name union all
      select 'seven' name union all -- neither %o% nor %i%
      select 'eight' name union all
      select 'nine'  name union all
      select 'ten'   name           -- neither %o% nor %i%
) numbers,
(
      select '%o%'  expression union all
      select '%i%'  expression       
) patterns
where
  numbers.name like patterns.expression

selects all records except three, seven and ten as expected.

Now, I am looking for a way to find these three records. I thought about left joining numbers with patterns and then filtering on the expression being null. Something like this:

numbers.name *like patterns.expression and
patterns.expression is null

Obviously, this doesn’t work. So, I’d be happy for any pointer given into the right direction.

For what’s its worth, this is the version I am working on:

select @@version
'Adaptive Server Enterprise/15.0.3/EBF 17156 ESD#3/P/Sun_svr4/OS 5.8/ase1503/2726/64-bit/FBO/Fri Feb  5 05:26:23 2010'
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1 Answer

  1. Editorial Team

    You should use NOT EXISTS (it’s the case):

    select numbers.name from 
(
      select 'one'   name union all
      select 'two'   name union all
      select 'three' name union all -- neither %o% nor %i%
      select 'four'  name union all
      select 'five'  name union all
      select 'six'   name union all
      select 'seven' name union all -- neither %o% nor %i%
      select 'eight' name union all
      select 'nine'  name union all
      select 'ten'   name           -- neither %o% nor %i%
) numbers
where not exists (select null
                    from (
                             select '%o%'  expression union all
                             select '%i%'  expression
                         ) patterns
                   where numbers.name like patterns.expression)
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