Question

I am stuck with FIND_IN_SET function in MYSQL 5.5, For example:

Please check below query, considering 10,9,5,8,21 are user id’s

SELECT u.user_id,u.first_name,u.last_name
FROM user u 
WHERE 
u.is_active = 'Y'       
AND FIND_IN_SET(u.user_id,'10,9,5,8,21');

When I fire this query it give me results in Ascending order of user id’s that is in

5
8
9
10
21

I want in same order like I entered

10
9
5
8
21

Is there any way to achieve it?

STORED PROCEDURE

DROP PROCEDURE IF EXISTS databaseName.procName;
DELIMITER //
CREATE PROCEDURE databaseName.procName(IN ZoneIDs LONGTEXT)

BEGIN       
        SELECT u.user_id,u.first_name,u.last_name

        FROM user u     
        WHERE u.is_active = 'Y'
        AND FIND_IN_SET(u.user_id,ZoneIDs); 

END //
DELIMITER ;

Answer 1

Try using it like this :

SELECT u.user_id,u.first_name,u.last_name
FROM user u 
WHERE u.is_active = 'Y' and u.user_id IN (10,9,5,8,21)
ORDER BY FIND_IN_SET(u.user_id,'10,9,5,8,21');

This uses IN to only select data where u.userid is in that list and then orders by your specific order using find_in_set

FIND_IN_SET returns the index of the first argument in the second argument – so I’m very surprised your query even worked …..