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Home/ Questions/Q 6218291
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T07:34:50+00:00 2026-05-24T07:34:50+00:00

I am suffering from a problem while i take the current url of the

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I am suffering from a problem while i take the current url of the page and spliting them into parts and then checking for the index.php phrase.So far i have done this:

  <?php
      $domain=$_SERVER['REQUEST_URI'];
      $values = parse_url($domains);
  $path = explode('/',$values['path']);
  if(array_search($path[2], "index.php"))
        {
          echo "hello";
        }
  ?>

but its not working so guys help me out and thank you in advance coz i know i will be satisfied by your answers.

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  1. Editorial Team
    Editorial Team
    2026-05-24T07:34:51+00:00Added an answer on May 24, 2026 at 7:34 am

    Try this:

    $pathToFile = $_SERVER['PHP_SELF'];
    
    $currentFilename = substr($pathToFile, strrpos($pathToFile, '/') + 1);
    
    if($currentFilename == 'index.php')
    {
        echo 'This file is index.php!';
    }
    
    1. $_SERVER['PHP_SELF'] is the path to the current file on the local system. Since you don’t care about the domain name or the query string, this is easier.
    2. strrpos($pathToFile, '/') gets the index of the last occurrence of / in $pathToFile.
    3. substr($pathToFile, strrpos($pathToFile, '/') + 1) get the portion of $pathToFile starting with the character after the index found by strrpos() in step 2.
    4. You should be left with only the filename in $currentFilename, which you can compare with whatever you choose.

    Note that this will match any index.php file, not just the one at your domain root. For example, if your site is located at http://example.com, http://example.com/subdir/index.php would also be true for $currentFilename == 'index.php'. If that’s not what you want, you’d do it a little differently.

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