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Home/ Questions/Q 6033233
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T05:27:14+00:00 2026-05-23T05:27:14+00:00

I am taking a calendar feed with a PHP file and I need to

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I am taking a calendar feed with a PHP file and I need to compare it to my database. If the $lastEdited variable is different than what is in the database, I need to change the record. I’m really new to SQL, so I’m not sure what to do. I just have Date_Edited set as a VARCHAR so I just need to compare the strings. I have this:

  $query = "SELECT * FROM  myTable  WHERE Event_ID='$id'";
  $result = mysql_query($query);

  if (!mysql_num_rows($result)) {
     mysql_query("INSERT INTO myTable (Event_ID, Date_added, Date_edited, Title)
     VALUES ('$id', '$dateAdded', '$lastEdited', '$title')");
  }

How do I compare $lastEdited to Date_edited and change the row if they are different?

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  1. Editorial Team
    Editorial Team
    2026-05-23T05:27:15+00:00Added an answer on May 23, 2026 at 5:27 am

    you need to do something like

    $row = mysql_fetch_array($result, MYSQL_ASSOC);
    
    if($lastEdited != $row['Date_added']){
       # run update query
         mysql_query("update myTable set 
             // here insert all update fields you need like
            Date_added = '$dateAdded', Date_edited = '$lastEdited' ,  Title = '$title'
            WHERE Event_ID='$id' ");
    
    }
    
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