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Editorial Team
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Asked: 2026-05-20T13:54:25+00:00

I am teaching myself PHP and MySQL, and I am trying to retrieve some

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I am teaching myself PHP and MySQL, and I am trying to retrieve some information from my database and put it into a table.

So far only the table column headers are showing up, and no information is showing up for each column. It is also taking ages for the PHP file to display.

Please can you point out the problem with my code.

<?php
mysql_connect("localhost",$username,$password);
mysql_select_db($dbname) or die("Unable to select Database");
$query = "SELECT * FROM table_1";
$result = mysql_query($query);
$numcount = mysql_num_rows($result);
echo "<h2>$numcount rows in table_1.</h2>";
mysql_close();
?>

<table border="0" cellspacing="4" cellpadding="2">
<tr>
<th><font face="Futura">Type |</font></th>
<th><font face="Futura">Name |</font></th>
<th><font face="Futura">Street |</font></th>
<th><font face="Futura">Address1 |</font></th>
<th><font face="Futura">Address2 |</font></th>
<th><font face="Futura">Town |</font></th>
<th><font face="Futura">County |</font></th>
<th><font face="Futura">Postcode |</font></th>
<th><font face="Futura">Number |</font></th>
<th><font face="Futura">Latitude,Longitude</font></th>
</tr>

<?php
$i=0;
while ($i < 843) {
$type = mysql_result($result,$i,"type");
$name = mysql_result($result,$i,"name");
$street = mysql_result($result,$i,"street");
$addr1 = mysql_result($result,$im,"address1");
$addr2 = mysql_result($result,$im,"address2");
$town = mysql_result($result,$im,"town");
$county = mysql_result($result,$im,"county");
$postcode = mysql_result($result,$im,"postcode");
$number = mysql_result($result,$im,"number");
$latlong = mysql_result($result,$im,"latlong");
}
?>

<tr>
<td><font face="Futura"><?php echo $type;?></font></td>
<td><font face="Arial, Helvetica, sans-serif"><?php echo $name;?></font></td>
<td><font face="Arial, Helvetica, sans-serif"><?php echo $street;?></font></td>
<td><font face="Arial, Helvetica, sans-serif"><?php echo $addr1;?></font></td>
<td><font face="Arial, Helvetica, sans-serif"><?php echo $addr2;?></font></td>
<td><font face="Arial, Helvetica, sans-serif"><?php echo $town;?></font></td>
</tr>
<?php
$i++;
?>
<?
echo "</table>"; 
?>
</body>
</html>
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1 Answer

  1. Editorial Team

    For a starter, you are having an infinite loop as $i is not being incremented inside the loop. If you increment $i, it should fix the problem. What is $im?

    The code should look like:

    <?php
$i=0;
while ($i < 843) {
    $type = mysql_result($result,$i,"type");
    $name = mysql_result($result,$i,"name");
    $street = mysql_result($result,$i,"street");
    $addr1 = mysql_result($result,$i,"address1");
    $addr2 = mysql_result($result,$i,"address2");
    $town = mysql_result($result,$i,"town");
    $county = mysql_result($result,$i,"county");
    $postcode = mysql_result($result,$i,"postcode");
    $number = mysql_result($result,$i,"number");
    $latlong = mysql_result($result,$i,"latlong");

?>

<tr>
<td><font face="Futura"><?php echo $type;?></font></td>
<td><font face="Arial, Helvetica, sans-serif"><?php echo $name;?></font></td>
<td><font face="Arial, Helvetica, sans-serif"><?php echo $street;?></font></td>
<td><font face="Arial, Helvetica, sans-serif"><?php echo $addr1;?></font></td>
<td><font face="Arial, Helvetica, sans-serif"><?php echo $addr2;?></font></td>
<td><font face="Arial, Helvetica, sans-serif"><?php echo $town;?></font></td>
</tr>
<?php
    $i++;
} // this is where the loop is ending.
?>
<?
mysql_close(); // close mysql connection after reading data
echo "</table>"; 
?>
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