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Home/ Questions/Q 986607
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T05:20:46+00:00 2026-05-16T05:20:46+00:00

I am totally lost in how I should do this. I’m trying to display

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I am totally lost in how I should do this.

I’m trying to display a top 100 most liked songs list. I have this part to find the most 100 liked songs:

SELECT like_song_id, COUNT(like_song_id)
AS occurances
FROM likes
GROUP BY like_song_id
ORDER BY occurances
DESC LIMIT 100;

That works fine, I get a list of the top songs in the right order. But I also need to other information in the result, the following:

I need to join the ‘songs’ table on song_id = like_song id. I also need to left outer join (or something) the ‘likes’ table again to see if the current user ($user_id (PHP)) likes any of the songs in the top 100 list already.

How do I do this?

EDIT:

This is the final query that worked for me, thanks!

SELECT *
FROM (
    SELECT like_song_id, COUNT(like_song_id) AS occurrences
    FROM likes
    GROUP BY like_song_id
    ORDER BY occurrences DESC
    LIMIT 100
) T1
JOIN songs ON songs.song_id = T1.like_song_id
LEFT OUTER JOIN likes ON likes.like_song_id = T1.like_song_id AND like_user_id = 1

ORDER BY occurrences DESC LIMIT 100
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T05:20:47+00:00Added an answer on May 16, 2026 at 5:20 am

    You could try a subselect:

    SELECT *
    FROM (
        SELECT like_song_id, COUNT(like_song_id) AS occurrences
        FROM likes
        GROUP BY like_song_id
        ORDER BY occurrences DESC
        LIMIT 100
    ) T1
    JOIN songs ON songs.song_id = T1.like_song id
    JOIN likes ON likes.like_song_id = T1.like_song id AND userid = 123
    
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