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Home/ Questions/Q 8501857
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T01:19:27+00:00 2026-06-11T01:19:27+00:00

I am trying loop on selected elements that queried with document.querySelectorAll, but how? For

  • 0

I am trying loop on selected elements that queried with document.querySelectorAll, but how?

For example I use:

var checkboxes = document.querySelectorAll('.check');
for( i in checkboxes) {
  console.log(checkboxes[i]);
}

Output:

<input id="check-1" class="check" type="checkbox" name="check">
<input id="check-2" class="check" type="checkbox" name="check">
<input id="check-3" class="check" type="checkbox" name="check">
<input id="check-4" class="check" type="checkbox" name="check">
<input id="check-5" class="check" type="checkbox" name="check">
<input id="check-6" class="check" type="checkbox" name="check">
<input id="check-7" class="check" type="checkbox" name="check">
<input id="check-8" class="check" type="checkbox" name="check">
<input id="check-9" class="check" type="checkbox" name="check">
<input id="check-10" class="check" type="checkbox" name="check" checked="">

10
item()
namedItem()

My problem is that at the end this method returns 3 extra items. How can I properly do it?

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  1. Editorial Team
    Editorial Team
    2026-06-11T01:19:30+00:00Added an answer on June 11, 2026 at 1:19 am

    for in loop is not recommended for arrays and array-like objects – you see why. There can be more than just number-indexed items, for example the length property or some methods, but for in will loop through all of them. Use either

    for (var i = 0, len = checkboxes.length; i < len; i++) {
        //work with checkboxes[i]
    }
    

    or

    for (var i = 0, element; element = checkboxes[i]; i++) {
        //work with element
    }
    

    The second way can’t be used if some elements in array can be falsy (not your case), but can be more readable because you don’t need to use [] notation everywhere.

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