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Home/ Questions/Q 7640125
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T08:35:41+00:00 2026-05-31T08:35:41+00:00

I am trying out prepared statements, but the below code is not working. I

  • 0

I am trying out prepared statements, but the below code is not working. I am getting the error:

Fatal error: Call to a member function execute() on a non-object in
/var/www/prepared.php on line 12

<?php

    $mysqli = new mysqli("localhost", "root", "root", "test");
    if ($mysqli->connect_errno) {
        echo "Failed to connect to MySQL: " . $mysqli->connect_error;
    }

    $stmt = $mysqli->prepare("INSERT INTO users (name, age) VALUES (?,?)");

    // insert one row
    $stmt->execute(array('one',1));

    // insert another row with different values
    $stmt->execute(array('two',1));
?>

Also, do I need to use mysqli for prepared statements? Can anyone point me to a complete example on prepared statements from connection to insertion to selection with error handling?

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  1. Editorial Team
    Editorial Team
    2026-05-31T08:35:43+00:00Added an answer on May 31, 2026 at 8:35 am

    From the mysqli::prepare docs:

    The parameter markers must be bound to application variables using mysqli_stmt_bind_param() and/or mysqli_stmt_bind_result() before executing the statement or fetching rows.

    bind_param docs.

    i.e.:

    $name = 'one';
    $age  = 1;
    
    $stmt = $mysqli->prepare("INSERT INTO users (name, age) VALUES (?,?)");
    
    // bind parameters. I'm guessing 'string' & 'integer', but read documentation.
    $stmt->bind_param('si', $name, $age);
    
    // *now* we can execute
    $stmt->execute();
    
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