Question

I am trying the following code:

<?php      $link = mysql_connect('localhost', 'root', 'geheim');     if (!$link) {         die('Could not connect: ' . mysql_error());     }     echo 'Connected successfully';        $query = 'SELECT * FROM Auctions';     $result = mysql_query($query);      while($row = mysql_fetch_array($result, MYSQL_ASSOC))     {         foreach($row as $field=>$value)         {             echo '$field: {$value} <br />';         }     }     mysql_close($link);  ?>  

And get this error:

Warning: mysql_fetch_array(): supplied argument is not a     valid MySQL result resource in     C:\Programme\EasyPHP 2.0b1\www\test.php on line 14 

What am I missing?

Answer 1

You haven’t selected a database – use mysql_select_db()

That would be something like:

<?php     $link = mysql_connect('localhost', 'root', 'geheim');     if (!$link) {         die('Could not connect: ' . mysql_error());     }     echo 'Connected successfully';      $db_selected = mysql_select_db('foo', $link);     if (!$db_selected) {         die ('Error selecting database: '. mysql_error());     }     echo 'Using database successfully';      $query = 'SELECT * FROM Auctions';     $result = mysql_query($query);     while($row = mysql_fetch_array($result, MYSQL_ASSOC)) {         foreach($row as $field=>$value) {             echo '$field: {$value} <br />';         }     }     mysql_close($link); ?>