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Home/ Questions/Q 6683647
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T04:50:45+00:00 2026-05-26T04:50:45+00:00

I am trying to add a new row to a table, after it is

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I am trying to add a new row to a table, after it is loaded (since I need to retrieve some data), but the new row just shows ‘undefined’. It looks like this:

$('#example tr').each( function () {
                id = this.id.substr(4);
                var result2;
                if (id.length > 0) {
                    $.post('get_stuff.php', {id: id}, function(result) {
                        result2 = result;
                    }); 
                    oTable.fnOpen( this, result2, "info_row_");
                }
            } );

The above opens the new rows and writes ‘undefined’ in them. If, however, before the fnOpen call I add an alert(result2) the result is shown in the alert and then written to the row. How can I solve this?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T04:50:46+00:00Added an answer on May 26, 2026 at 4:50 am

    Your $.post() request is asynchronous.

    So the info is written while it is still being requested.

    You could either add:

    $.ajaxSetup({async:false}); before the .post() call or use .ajax() with async: false option.

    .post() is just a shorthand version of .ajax()

    Or you could write the vakue in the success callback of the .post() function.

    $.post('get_stuff.php', {id: id}, function(result) {
      //result2 = result; // don't know if you still need the result2 var somewhere else. If that's the case you should use one of the other approaches (as stated above)
      oTable.fnOpen( this, result, "info_row_");
    }); 
    
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