Question

I am trying to add data to a row in a dataset but the data is always on a new row?

I need the data to populate under its column. I need something like Ds.Tables[0].Rows[1].add("Item")

This is how i am inserting the data:

DataSet ds = new DataSet();
            ds.Tables.Add("Properties");
            //GPS
            ds.Tables[0].Columns.Add(ArrayProperties[0].FormMobiField);
            ds.Tables[0].Rows.Add(ArrayProperties[0].Value);
            //Street Num and Name
            ds.Tables[0].Columns.Add(ArrayProperties[3].FormMobiField);      
            ds.Tables[0].Rows.Add(ArrayProperties[3].Value);
            //Suburb
            ds.Tables[0].Columns.Add(ArrayProperties[6].FormMobiField);
            ds.Tables[0].Rows.Add(ArrayProperties[6].Value);
            //City
            ds.Tables[0].Columns.Add(ArrayProperties[7].FormMobiField);
            ds.Tables[0].Rows.Add(ArrayProperties[7].Value);
            //Province
            ds.Tables[0].Columns.Add(ArrayProperties[8].FormMobiField);
            ds.Tables[0].Rows.Add(ArrayProperties[8].Value);
            //Locality Map
            ds.Tables[0].Columns.Add(ArrayProperties[9].FormMobiField);
            ds.Tables[0].Rows.Add(ArrayProperties[9].Value);
            //Property Type
            ds.Tables[0].Columns.Add(ArrayProperties[10].FormMobiField);
            ds.Tables[0].Rows.Add(ArrayProperties[10].Value);

Answer 1

Just get a new Row from the DataTable and then add that row to the table, Use DataTable.NewRow method

DataRow dr = ds.Tables[0].NewRow();
dr["Column1"] = "value";
dr["Column2"] = "value";
dr["Column3"] = "value";

ds.Tables[0].Rows.Add(dr);

You are adding row after adding each column, You may first create your data table’s structure by adding all the columns and then you can get the new row using DataTable.NewRow() and later you can add that row to your data table. After adding all the columns you may also try:

ds.Tables[0].Rows.Add(ArrayProperties[0].Value,ArrayProperties[1].Value,ArrayProperties[2].Value,ArrayProperties[3].Value);