Question

I am trying to add files into a zip by sending the file names from a HTML form.
The HTML code is

<form action="act.php" method="POST">
<input type="checkbox" name="send1" value="filename1.extension">
<input type="checkbox" name="send1" value="filename2.extension">
</form>

The PHP

I tried in two ways
Method 1:

$zipfilename="abcd.zip";
$zip= new ZipArchive();
$zip->open($zipfilename, ZipArchive::CREATE);
foreach($_POST['send1'] as $filename)
{
$zip->addFile($filename);
}
$zip->close();

Method 2:

$zipfilename="abcd.zip";
$filestozip=array();
foreach($_POST['send1'] as $filename)
{
$filestozip[]=$filename;
}

$zip= new ZipArchive();
$zip->open($zipfilename, ZipArchive::CREATE);

foreach($filestozip as $filename2)
{
$zip->addFile($filename2);}
}

$zip->close();

But the Zip File is not getting created. I tried to check the Zip syntax with static code for $filetozip as

$filestozip[0]="filename1.extension";
$filestozip[0]="filename1.extension";

It worked. But when the data is from another HTML page dynamically it does not work. What is the error in my code?

Answer 1

Found the problem. There is no problem in my logic.

$zip->addFile($filename);

As I said previous the data for the $filename variable is received from a HTML for in which any spaces are replaced by %20 intentionally by me. The reason for such replacement is to enable links to the file using the data. But if the space is replaced by %20 zipArchive::addFile() does not add the zip file which ultimately result in Zip creation fail.