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Home/ Questions/Q 53211
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Asked: May 10, 20262026-05-10T17:01:40+00:00 2026-05-10T17:01:40+00:00

I am trying to automate functional testing of a server using a realistic frequency

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I am trying to automate functional testing of a server using a realistic frequency distribution of requests. (sort of load testing, sort of simulation)

I’ve chosen the Weibull distribution as it ‘sort of’ matches the distribution I’ve observed (ramps up quickly, drops off quickly but not instantly)

I use this distribution to generate the number of requests that should be sent each day between a given start and end date

I’ve hacked together an algorithm in Python that sort of works but it feels kludgy:

how_many_days = (end_date - start_date).days freqs = defaultdict(int) for x in xrange(how_many_responses):     freqs[int(how_many_days * weibullvariate(0.5, 2))] += 1 timeline = [] day = start_date for i,freq in sorted(freqs.iteritems()):     timeline.append((day, freq))     day += timedelta(days=1) return timeline 

What better ways are there to do this?

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  1. 2026-05-10T17:01:41+00:00Added an answer on May 10, 2026 at 5:01 pm

    This is quick and probably not that accurate, but if you calculate the PDF yourself, then at least you make it easier to lay several smaller/larger ones on a single timeline. dev is the std deviation in the Guassian noise, which controls the roughness. Note that this is not the ‘right’ way to generate what you want, but it’s easy.

    import math from datetime import datetime, timedelta, date from random import gauss  how_many_responses = 1000 start_date = date(2008, 5, 1) end_date = date(2008, 6, 1) num_days = (end_date - start_date).days + 1 timeline = [start_date + timedelta(i) for i in xrange(num_days)]  def weibull(x, k, l):     return (k / l) * (x / l)**(k-1) * math.e**(-(x/l)**k)  dev = 0.1 samples = [i * 1.25/(num_days-1) for i in range(num_days)] probs = [weibull(i, 2, 0.5) for i in samples] noise = [gauss(0, dev) for i in samples] simdata = [max(0., e + n) for (e, n) in zip(probs, noise)] events = [int(p * (how_many_responses / sum(probs))) for p in simdata]  histogram = zip(timeline, events)  print '\n'.join((d.strftime('%Y-%m-%d ') + '*' * c) for d,c in histogram) 
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