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Asked: 2026-06-12T17:45:51+00:00

I am trying to build a db driven web site in which the user

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I am trying to build a db driven web site in which the user selects from a drop down menu a
value and some Information from a database are returned. I use an ajax post cause i dont want the page to get refreshed:

$("#button").click(function(){ 
   var datastr = ($('#act').val());
   var datastr1 = ($('#loc').val());

   $.ajax({
      type:'POST',
      url:'activities_code.php',
      data: {datastr:datastr, datastr1:datastr1},
      success:function(response){
                $("#msg").html(response);                       
            } });});

In the url parameter I have the following php file (this is a part of the php file): 

 $query = "SELECT PK,title,Information from activities where Activities='$category'";
    $result = mysqli_query($dbcon, $query) or die('no available data');

    echo "<table>";
$num_results = 0;
$t = 0; //title counter for the id of each title
while ($row=mysqli_fetch_array($result, MYSQLI_ASSOC)) {
     // Here the columns of title and information are printed
     echo "<tr><td>";
     echo "<a href='test.php'  id=\"t\".$t onClick=\"test()\" target=\"_new\" >".$row['title']."</a>"; 
     echo "<br>";
     echo  $x = $row['PK'];
     echo "</td></tr>";


     echo "<tr><td>";
     echo $row['Information'];
     echo "</td></tr>";
// Here I sum up the number of the results
     $num_results=$num_results+1;   
     $t = $t+1;      
 }

}

As you can see, I have a while loop in which I echo each time a link with an id:

"<a href='test.php'  id=\"t\".$t onClick=\"test()\" target=\"_new\" >".$row['title']."</a>";

What I want to do is to use this id of each link later in my code by doing something like this:

  document.getElementById("t1").value

My question is, how can I return this id’s to the client side? I think I should write something in the success function but I have no idea what.
If you dont understand some part of the code or I didn’t explain everything clear, please ask me.
Thanks
D.

This is what I get when I alert(response) in the success function.

<!DOCTYPE HTML>




       <table id="container"><tr><td><a href='test.php' id="t0" target="_new"   class='pickanchor'>Rafting in Voidomatis</a><br>1</td></tr><tr><td>
      <img src="m.jpg" class="textwrap" height="120px" width="120px">
      <p style="text-align:left;">Our experienced rafting instructors will show you the best way to enjoy Voidomatis, the river with the most clear waters inSouth Europe. You can also cross the Vikos Gorge by following Voidomatis river in an attractive one and a half hour   long walk. Alternatively you can ask for the more demanding Aoos river rafting.</p>
     <br>
     <br>
     <hr></td></tr><tr><td><a href='test.php' id="t1" target="_new" class='pickanchor'>Rafting   in Lousios</a><br>4</td></tr><tr><td><img src="raf.jpg" class="textwrap" height="120" width="120">
     <p>You will be surprised to know that Greece hides numerous, densely vegetated rivers offering amazing rafting opportunities. In the whole mainland, there is a company base awaiting you, for an amazing � off the beaten track experience!</p>
     <br>
     <br>
     <br>
     <hr></td></tr><div id="r2" align="center" id="result_2">2 results for rafting were found!        
     </div></table>  <!-- End of PHP code-->
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1 Answer

  1. Editorial Team

    First, There is problem with ID of your anchor tag. here is correction

    "<a href='test.php'  id=\"t".$t."\" onClick=\"test()\" target=\"_new\" >".$row['title']."</a>";

    Second, Give id to your table like

    <table id="container">

    Third, give class to your anchor tag.

    "<a href='test.php' class='pickanchor'  id=\"t.$t\" onClick=\"test()\" target=\"_new\" >".$row['title']."</a>";

    Now write following code into your success handle after .html() statement

    NEW EDIT

    $("a.pickanchor").each(function(i){

   alert(this.id);
});
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