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Home/ Questions/Q 6100025
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T13:20:22+00:00 2026-05-23T13:20:22+00:00

I am trying to build a Python deamon which listen to a queue (Redis

  • 0

I am trying to build a Python deamon which listen to a queue (Redis Kombu).
Grab the task and spawn a greenthread to process this task.

I can receive the task and consume it without trouble but when I try to spawn a GreenThread with eventlet it does not seem to be doing anything at all.

No print, no logging is shown.

class agent(Daemon):
    """
    Agent
    """
    def run(self):  
        # Setup connection
        mainLogger.debug('Connecting to Redis')
        connection = BrokerConnection(
                        hostname=agentConfig['redis_host'],
                        transport="redis",
                        virtual_host=agentConfig['redis_db'],
                        port=int(agentConfig['redis_port']))
        connection.connect()

        # Create an eventlet pool of size 5
        pool = eventlet.GreenPool(5)
        q = connection.SimpleQueue("myq")
        while True:
            try:
               message = q.get(block=True, timeout=1)
               print "GOT A MESSAGE FROM Q !"
               pool.spawn_n(self.foo, 'x')
               print "END SPAWN !"
            except Empty:
               mainLogger.debug('No tasks, going to sleep')
               time.sleep(1)


    def foo(self, x):
        mainLogger.debug('\o/')
        print "HELLO FROM SPAWN"

Anything I am doing wrong ?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T13:20:23+00:00Added an answer on May 23, 2026 at 1:20 pm

    I needed to call eventlet.monkey_patch() for sleep() call to trigger context switching.

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