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Home/ Questions/Q 6689691
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T05:32:56+00:00 2026-05-26T05:32:56+00:00

I am trying to calculate a definite integral. I write: NIntegrate[expression, {x, 0, 1},

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I am trying to calculate a definite integral. I write:

NIntegrate[expression, {x, 0, 1}, WorkingPrecision -> 100]

“expression” is described below. The WorkingPrecision was added in to help with another error.

I get an error:

“NIntegrate::ncvb: NIntegrate failed to converge to prescribed
accuracy after 9 recursive bisections in x near {x} = {<<156>>}.
NIntegrate obtained <<157>> and <<160>> for the integral and error
estimates. >>”

Why am I getting this error for near{x} = {<<156>>} when I am only looking at 0<x<1? And what do the double pointy brackets around the number mean?

The expression is really long, so I think it would be more meaningful to show how I generate it.This is a basic version (some of the exponents I need to be variables, but these are the lowest values, and I still get the error).

F[n_] := (1 - (1 - F[n-1])^2)^2;
F[0] = x;
Expr[n_]:= (1/(1-F[n]))Integrate[D[F[n],x]*x,{x,x,1}];

I get the error when I integrate Expr[3] or higher. Oddly, when I use regular Integrate and then //N at the end, I get a complex number for n=2.

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  1. Editorial Team
    Editorial Team
    2026-05-26T05:32:57+00:00Added an answer on May 26, 2026 at 5:32 am

    The <<156>> does not mean that the integral is being evaluated at x=156. <<>> is called Skeleton and is used to indicate that a large output was suppressed. From the documentation:

    Skeleton[n]
    represents a sequence of n omitted elements in an expression printed with Short or Shallow. The standard print form for Skeleton is <<n>>.


    Coming to your integral, here’s the error that I get:

    enter image description here

    So you can see that this long number was suppressed in your case (depending on your preferences). The last >> is a link that takes you to the corresponding error message in the documentation.

    If you try the advice in the document, which is to increase MaxRecursion, you’ll eventually get a new error ::slwcon

    enter image description here

    So this now tells you that either your WorkingPrecision is too small or that you have a singularity (which is brought on by a small working precision). Increasing WorkingPrecision to 200 gives the following output:

    enter image description here


    You can look a little further into the nature of your expressions.

    num = Numerator@Expr@3;
    den = Denominator@Expr@3;
    Plot[{num, den}, {x, 0, 1}, WorkingPrecision -> 100, PlotRange -> All]
    

    enter image description here

    So beyond 0.7ish, your expression has the potential for serious stability issues, resulting in singularities. It is the numerator rather than the denominator, that requires high precision to converge to the right value.

    num /. x -> 0.99
    num /. x -> 0.99`100
    
    Out[1]= -0.015625
    Out[2]= 1.2683685178049112809413795626911317545171610885215799438968\
    06379991565*10^-14
    
    den /. x -> 0.99
    den /. x -> 0.99`100
    
    Out[3]= 1.28786*10^-14
    Out[4]= 1.279743968014714505561671861369465844697720803022743298030747945923286\
    915425027352809730413954909*10^-14
    

    You can see here the difference between the numerator and denominator when you don’t have sufficient precision, causing a near singularity.

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