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Asked: 2026-05-25T16:06:31+00:00

I am trying to calculate the convolution of x(t) = 1, -1<=t<=1 x(t) =

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I am trying to calculate the convolution of 

x(t) = 1, -1<=t<=1
x(t) = 0, outside

with itself using the definition.

http://en.wikipedia.org/wiki/Convolution

I know how to do using the Matlab function conv, but I want to use the integral definition. My knowledge of Matlab and WolframAlpha is very limited.

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1 Answer

  1. Editorial Team

    I am still learning Mathematica myself, but here is what I came up with..

    First we define the piecewise function (I am using the example from the Wikipedia page)

    f[x_] := Piecewise[{{1, -0.5 <= x <= 0.5}}, 0]

    piecewise_function

    Lets plot the function:

    Plot[f[x], {x, -2, 2}, PlotStyle -> Thick, Exclusions -> None]

    function_plot

    Then we write the function that defines the convolution of f with itself:

    g[t_] = Integrate[f[x]*f[t - x], {x, -Infinity, Infinity}]

    convolution_integral

    and the plot:

    Plot[g[t], {t, -2, 2}, PlotStyle -> Thick]

    convolution_plot

    EDIT

    I tried to do the same in MATLAB/MuPad, I wasn’t as successful:

    f := x -> piecewise([x < -0.5 or x > 0.5, 0], [x >= -0.5 and x <= 0.5, 1])

    func_def

    plot(f, x = -2..2)

    func_plot

    However when I try to compute the integral, it took almost a minute to return this:

    g := t -> int(f(x)*f(t-x), x = -infinity..infinity)

    convolution

    the plot (also took too long)

    plot(g, t = -2..2)

    convolution_plot

    Note the same could have been done from inside MATLAB with the syntax:

    evalin(symengine,'<MUPAD EXPRESSIONS HERE>')
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