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Home/ Questions/Q 7093349
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T08:25:42+00:00 2026-05-28T08:25:42+00:00

I am trying to call a function from a shared object using ruby-ffi. I

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I am trying to call a function from a shared object using ruby-ffi. I compiled the following into a shared object:

#include <stdio.h>

typedef struct _WHAT {
  int d;
  void * something;
} WHAT;

int doit(WHAT w) {
  printf("%d\n", w.d);
  return w.d;
}

The problem is, how do I declare the function with attach_function in Ruby? How is the struct argument (WHAT w) defined in the list of arguments in Ruby? It is not a :pointer, and does not seem to fit any of the other available types described in the ruby-ffi documentation, so what would it be?

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  1. Editorial Team
    Editorial Team
    2026-05-28T08:25:42+00:00Added an answer on May 28, 2026 at 8:25 am

    Check how to use Structs in https://github.com/ffi/ffi/wiki/Structs, for your case:

    class What < FFI::Struct
      layout :d, :int,
             :something, :pointer
    end
    

    Now attach the function, the argument, since you are passing the struct by value, is going to be What.by_value(replacing What by whatever you have named you struct class above):

    attach_function 'doit', [What.by_value],:int
    

    And now how to call the function:

    mywhat = DoitLib::What.new
    mywhat[:d] = 1234
    DoitLib.doit(mywhat)
    

    And now the complete file:

    require 'ffi'
    
    module DoitLib
      extend FFI::Library
      ffi_lib "path/to/yourlibrary.so"
    
      class What < FFI::Struct
        layout :d, :int,
               :something, :pointer
      end
    
      attach_function 'doit', [What.by_value],:int
    
    end
    
    mywhat = DoitLib::What.new
    mywhat[:d] = 1234
    DoitLib.doit(mywhat)
    
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