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Home/ Questions/Q 3795534
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T13:05:54+00:00 2026-05-19T13:05:54+00:00

I am trying to call GetFileInformationByHandle on the executable of my own running program.

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I am trying to call GetFileInformationByHandle on the executable of my own running program. This means I’ll need to get a file handle to the .exe that started my program. Is there any way to do this?

Failing that, is there any way to get the nFileIndexHigh and nFileIndexLow for a running executable?

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  1. Editorial Team
    Editorial Team
    2026-05-19T13:05:55+00:00Added an answer on May 19, 2026 at 1:05 pm

    Here it is a way to do this. I hope this helps:

    #include <Windows.h>
    #include <iostream>
    using namespace std;
    
    //declare a BY_HANDLE_FILE_INFORMATION structure
    BY_HANDLE_FILE_INFORMATION fileinfo;
    
    int main()
    {
        // clear everything in the structure, this is optional
        ZeroMemory(&fileinfo, sizeof(BY_HANDLE_FILE_INFORMATION));
    
        // obtain a handle to the file, in this case the file
        // must be in the same directory as your application
        HANDLE myfile = NULL;
        myfile = CreateFileA("example.exe",0x00,0x00,NULL,
                             OPEN_EXISTING,FILE_ATTRIBUTE_NORMAL,NULL);
    
        // if we managed to obtain the desired handle
        if(myfile!=INVALID_HANDLE_VALUE)
        {
            //try to fill the structure with info regarding the file
            if(GetFileInformationByHandle(myfile, &fileinfo))
            {
                // Ex: show the serial number of the volume the file belongs to
                cout << endl << hex << fileinfo.dwVolumeSerialNumber << endl;
            }
            // you should close the handle once finished
            CloseHandle(myfile);
        }
        system("pause");
        return 0;
    }
    
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