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Home/ Questions/Q 145865
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Editorial Team
Asked: May 11, 20262026-05-11T08:29:58+00:00 2026-05-11T08:29:58+00:00

I am trying to clean up some data, and I would eventually like to

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I am trying to clean up some data, and I would eventually like to put it in CSV form.

I have used some regular expressions to clean it up, but I’m stuck on one step.

I would like to replace all but every third newline (\n) with a comma.

The data looks like this:

field1 field2 field3 field1 field2 field3 

etc..

I need it in

field1,field2,field3 field1,field2,field3 

Anyone have a simple way to do this using sed or awk? I could write a program and use a loop with a mod counter to erase every 1st and 2nd newline char, but I’d rather do it from the command line if possible.

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  1. 2026-05-11T08:29:58+00:00Added an answer on May 11, 2026 at 8:29 am

    With awk:

    awk '{n2=n1;n1=n;n=$0;if(NR%3==0){printf'%s,%s,%s\n',n2,n1,n}}' yourData.txt 

    This script saves the last three lines and print them at every third line. Unfortunately, this works only with files having a multiple of 3 lines.

    A more general script is:

    awk '{l=l$0;if(NR%3==0){print l;l=''}else{l=l','}}END{if(l!=''){print substr(l,1,length(l)-1)}}' yourData.txt 

    In this case, the last three lines are concatenated in a single string, with the comma separator inserted whenever the line number is not a multiple of 3. At the end of the file, the string is printed if it is not empty with the trailing comma removed.

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