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Home/ Questions/Q 6150365
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T19:36:13+00:00 2026-05-23T19:36:13+00:00

I am trying to code a lazy version of Sieve of Eratosthenes in Python

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I am trying to code a lazy version of Sieve of Eratosthenes in Python 3.2. Here’s the code:

import itertools
def primes():
    candidates = itertools.count(2)
    while True:
        prime = next(candidates)
        candidates = (i for i in candidates if i % prime)
        yield prime

However, when I iterate over primes(), I only get consecutive numbers. E.g.,

print(list(itertools.islice(primes(),0,10)))

prints the list

[2, 3, 4, 5, 6, 7, 8, 9, 10, 11]

To my surprise, the following tiny modification of primes() makes it work:

def primes():
    candidates = itertools.count(2)
    while True:
        prime = next(candidates)
        candidates = (i for i in candidates if i % prime)
        next(itertools.tee(candidates)[1]) ########### NEW LINE
        yield prime

I am guessing I am missing something about the scope of the parameters of the generator

candidates = (i for i in candidates if i % prime)

but I cannot see how to fix the code without adding this random-looking new line. Does anybody know what I am doing wrong? Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-23T19:36:14+00:00Added an answer on May 23, 2026 at 7:36 pm

    the fix is really to replace:

    candidates = (i for i in candidates if i % prime)
    

    with:

    candidates = (lambda prime: (i for i in candidates if i % prime))(prime)
    
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