Question

i am trying to code a search function to search in strings and find the word

like the php + mysql for example

Select * From Column Where ID Like %Word%

i tried to code the same idea with Preg match all and regex

Here is my code

$strings = '
( monstername 205 "Devil Troop of Desire")
( monstername 206 "  Devil Troop of Pain     "  )
( monstername 207       "Devil Troop of Greed")
( monstername 208   "       Devil Troop of Jealousy  ")
( monstername 207 "Mask Troop of Greed"  )';

preg_match_all('/monstername\s*(.*?)\s*\"\s*\\b(Jealousy)\b\s*\"\s*\)/i', $strings, $matches, PREG_SET_ORDER);
foreach ($matches as $match){list (, $MonsterNumber) = $match;
echo "$MonsterNumber";
}

the output should be

208

but it dont display the output correct

it display it when i replace Jealousy With Devil Troop of Jealousy

i just want to do the same idea of php + mysql

Where ID Like %Word%

without give the full string to find the number of monster

Answer 1

The part "\s*\\b(Jea does not allow for other characters than whitespace between the quote and the start of the word. You probably wanted any char (or even none?) between them, like ".*\\b(Jea and the same problem after the word.