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Home/ Questions/Q 8044369
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T05:12:35+00:00 2026-06-05T05:12:35+00:00

I am trying to combined these two script (a file upload) and (a mysql

  • 0

I am trying to combined these two script (a file upload) and (a mysql update) so that the image file is both uploaded to the correct folder and the file path is then updated in the mysql database. I know the $sql update query is wrong and thats where my trouble is. Any help would be great.

//db connection
require "connect.db.php";

if ((($_FILES["file"]["type"] == "image/gif")
|| ($_FILES["file"]["type"] == "image/jpeg")
|| ($_FILES["file"]["type"] == "image/pjpeg"))
&& ($_FILES["file"]["size"] < 20000))
  {
  if ($_FILES["file"]["error"] > 0)
    {
    echo "Return Code: " . $_FILES["file"]["error"] . "<br />";
    }
  else
    {
    echo "Upload: " . $_FILES["file"]["name"] . "<br />";
    echo "Type: " . $_FILES["file"]["type"] . "<br />";
    echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />";
    echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br />";

    if (file_exists("upload/" . $_FILES["file"]["name"]))
      {
      echo $_FILES["file"]["name"] . " already exists. ";
      }
    else
      {
      move_uploaded_file($_FILES["file"]["tmp_name"],
      "upload/" . $_FILES["file"]["name"]);
      echo "Stored in: " . "upload/" . $_FILES["file"]["name"];
      }
    }
  }
else
  {
  echo "Invalid file";
  }

// update data in mysql database
$sql="UPDATE `characters` SET ch_image='/upload/$_FILES["file"]["name"]' WHERE ID='$id'";
$result=mysql_query($sql);

// if successfully updated.
if($result){
echo "Successful";
echo "<BR>";
echo "<a href='test.html'>View result</a>";
touch('../file.html');
clearstatcache();
}

else {
echo "Whoops: " . mysql_error(); ;
}
mysql_close();
?>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-05T05:12:35+00:00Added an answer on June 5, 2026 at 5:12 am

    change $sql to this

    $sql="UPDATE `characters` SET ch_image='/upload/" . $_FILES['file']['name'] . "' WHERE ID='$id'";
    
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