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Home/ Questions/Q 5981615
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T21:58:07+00:00 2026-05-22T21:58:07+00:00

I am trying to compare if the value of one BigInteger(base) is > (greater

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I am trying to compare if the value of one BigInteger(base) is > (greater than) the value of another BigInteger(prime) and if the value of ‘a’ is not equal to one. If value of a is not 1, it should break out of the loop. How should I compare them?

Random ran = new Random();
BigInteger prime = new BigInteger(16,ran);
BigInteger base,a,one;
one = new BigInteger("1");

for (int i = 0; i < 65535; i++){

    while (base>prime){
        base = new BigInteger(16,ran);
    }
    a = base.modPow(prime.subtract(one),prime);
    System.out.println("a: "+a);    
    if (a != one){
        break;          
    }   
}
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  1. Editorial Team
    Editorial Team
    2026-05-22T21:58:08+00:00Added an answer on May 22, 2026 at 9:58 pm

    You can compare them using BigInteger.compareTo(BigInteger).

    In your case, this would be while (base.compareTo(prime) > 0) {...}.

    Also, your termination condition should be changed from if (a != one) to if (!a.equals(one)) since two BigInteger variables with the same integer value are not necessarily referencing the same object (which is all that == and != test).

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