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Home/ Questions/Q 8270049
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T06:26:23+00:00 2026-06-08T06:26:23+00:00

I am trying to compare the following: if the value is not an array

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I am trying to compare the following: if the value is not an array or the value does not equal false, return.

if (is_array($value) != true || $value != false) return;

This, and any other variation I am trying doesnt seem to work. However, when I compare these individually in their own if statements they return the correct results.

Any help would be greatly appreciated!

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  1. Editorial Team
    Editorial Team
    2026-06-08T06:26:26+00:00Added an answer on June 8, 2026 at 6:26 am

    You originally said “if it’s not an array or not false”. You’re thinking backwards. You want “if the value is an array or false continue, else return”.

    So:

    // This says: "if it's not (an array or false)"
    if(!(is_array($value) || $value === FALSE)) return;
    

    Using De Morgan’s laws, we can convert this to

    // This says: "if it's not an array and not false"
    if(!is_array($value) && $value !== FALSE) return;
    
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