Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 4612842
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 22, 20262026-05-22T01:27:37+00:00 2026-05-22T01:27:37+00:00

I am trying to conceive a solution for problems like in the following example:

  • 0

I am trying to conceive a solution for problems like in the following example:

A != B
B != C
D != B
C != B
E != D
E != A

How many variables are true and how many are false? As far as I found out I should try to use breadth-first search, but my problem is where to start and the fact that the graph will be an oriented one (I am connecting xi to !xj where the equality relation exists). Can someone point me in the right direction?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-22T01:27:37+00:00Added an answer on May 22, 2026 at 1:27 am

    It’s a graph 2-coloring problem. Vertices: A, B, C, … Edge (u, v) in this undirected graph is present if and only if u != v.

    2-coloring is one of the applications of the breadth-first search. See: http://en.wikipedia.org/wiki/Breadth-first_search#Testing_bipartiteness

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Trying to figure out how to read in multiple variables through a file. for
Trying to figure out how to convert how to covert 5 variables I have
Trying to get my css / C# functions to look like this: body {
Trying to make a MySQL-based application support MS SQL, I ran into the following
Trying to create a QtRuby application, I get the following error: /usr/lib64/ruby/site_ruby/1.8/Qt/qtruby4.rb:2144: [BUG] Segmentation
Trying to do this sort of thing... WHERE username LIKE '%$str%' ...but using bound
Trying to honor a feature request from our customers, I'd like that my application,
Trying to figure out why my vertex shader works on my cell phone (Casio
Trying to connect to a SQL Server 2005 instance remotely but getting the following
I am trying to conceive of a way in which I can float a

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.