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Home/ Questions/Q 6360433
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T23:38:56+00:00 2026-05-24T23:38:56+00:00

I am trying to convert all files in a given directory with suffix .foo

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I am trying to convert all files in a given directory with suffix “.foo” to files containing the same basename but with suffix modified to “.bar”. I am able to do this with a shell script and a for loop, but I want to write a one-liner that will achieve the same goal.

Objective:
  Input: *.foo
  Output: *.bar

This is what I have tried:

find . -name "*.foo" | xargs -I {} mv {} `basename {} ".foo"`.bar

This is close but incorrect. Results:
  Input: *.foo
  Output: *.foo.bar

Any ideas on why the given suffix is not being recognized by basename? The quotes around “.foo” are dispensable and the results are the same if they are omitted.

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  1. Editorial Team
    Editorial Team
    2026-05-24T23:38:57+00:00Added an answer on May 24, 2026 at 11:38 pm

    Although basename can work on file extensions, using the shell parameter expansion features is easier:

    for file in *.foo; do mv "$file" "${file%.foo}.bar"; done
    

    Your code with basename doesn’t work because the basename is only run once, and then xargs just sees {}.bar each time.

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